🏠 首页 CHAPTER 6 · ANGLES AND PARALLEL LINES 6.2

6.2

Angles

💡 本节先学角的分类(锐角 / 直角 / 钝角 / 反射角),再学角的性质(一条直线上邻角之和 = 180°,一点处所有角之和 = 360°,对顶角相等)。这些是几何题的基本工具。

AAngles and Measurements

When two line segments meet at a common point, they form an angle at that point. The point where the line segments meet is called a vertex. In the diagram, the angle with vertex $A$ and sides $AB$ and $AC$ are marked.

x vertex A C B side side

We denote this angle by

  • $\angle BAC$ or $\angle CAB$  (an angle symbol and three capital letters)
  • or $\angle x$.  (an angle symbol and a small letter)

$\angle BAC$ can also be written as $B\hat{A}C$.

The commonly used unit for measuring an angle is the degree and it is denoted by the symbol °. A complete rotation about a point is equal to 360°.

A B 360°

BTypes of Angles

We classify an angle according to its size. Let us look at the different types of angles: acute angle, right angle, obtuse angle and reflex angle.

(a) Acute angle
a
$\angle a < 90°$
(b) Right angle
b
$\angle b = 90°$
(c) Obtuse angle
c
$90° < \angle c < 180°$
(d) Reflex angle
d
$180° < \angle d < 360°$

📌 SPOTLIGHT:
• A right angle is usually marked by the symbol "" (small square in the corner).
• An angle of 180° is called a straight angle.

Is it true that half the size of a reflex angle can be an acute angle? Explain your answer.
💡 思考

反射角范围:$180° < d < 360°$,所以 $d/2$ 范围:$90° < d/2 < 180°$。这是钝角的范围,是锐角。所以"反射角的一半是锐角"不可能。

Look at the two diagrams below. Each diagram has two angles at points $B$ and $Q$. $\angle ABC$ is an acute angle and $\angle PQR$ is an obtuse angle. We refer to the reflex angles at points $B$ and $Q$ as reflex $\angle ABC$ and reflex $\angle PQR$, respectively.

A B C acute reflex P Q R obtuse reflex

Now, let us look at how we can classify different pairs of angles according to the relationship between each pair.

① Complementary angles · 互余

If the sum of two angles is 90°, then the two angles are called complementary angles.

Examples: $\angle ABD$ and $\angle DBC$ (both at $B$, summing to 90°); $\angle PQR$ and $\angle PRQ$ (in a right triangle).

② Supplementary angles · 互补

If the sum of two angles is 180°, then the two angles are called supplementary angles.

③ Adjacent angles · 邻角

If two angles share a common side and a common vertex but do not overlap, then the two angles are called adjacent angles.

📝 EXTRAINFO: Complementary angles and supplementary angles do not have to be adjacent but they can be.

📌 SPOTLIGHT: When two lines intersect at right angles, they are said to be perpendicular to each other. We write $AB \perp CD$. Two right angles form a pair of supplementary angles.

CProperties of Angles

Adjacent Angles on a Straight Line

In the diagram, $ABC$ is a straight line. The three angles, $\angle a$, $\angle b$ and $\angle c$, are adjacent angles on a straight line. $\angle a + \angle b + \angle c = 180°$.

c b a A B C
The sum of adjacent angles on a straight line is 180°.
(Abbreviation: adj. ∠s on a st. line)
📖 Worked Example 2

In the diagram, $ABC$ is a straight line. Find the value of $x$.

A B C D E 2x°

SOLUTION

  • $2x + 90 + x = 180$  (adj. ∠s on a st. line)
  • $3x = 180 - 90$
  • $3x = 90$
  • $x = \dfrac{90}{3}$
  • ∴ $x = \mathbf{30}$

📌 SPOTLIGHT: If an angle is marked with a letter and a degree symbol, such as $x°$, then $x$ represents a number and does not have a unit. The middle ray from $B$ in this diagram is perpendicular to $AC$ (right-angle mark not drawn but assumed for the 90° in the equation).

📌 NOTE: Always state the angle property which you have applied in your working.

✍️ Try It Yourself 2
  1. (a) In the diagram, $XYZ$ is a straight line. Find the value of $w$.
    X Y Z U V 140°
    $w = $ 检查
    💡 思路

    三个角在 $XYZ$ 直线上:$w + 140 + w = 180 \Rightarrow 2w = 40 \Rightarrow w = 20$.

  2. (b) In the diagram, $AOB$ is a straight line. The angles at $O$ are $(a+55)°$ (between $OA$ and $OD$), $(35-a)°$ (between $OC$ and $OB$), and the rays $OC$, $OD$ make up the middle. What is the relationship between $OC$ and $OD$? Explain.
    💡 思路

    $AOB$ 直线,所以 $(a+55) + \angle COD + (35-a) = 180 \Rightarrow \angle COD = 180 - 90 = 90°$. 所以 $OC \perp OD$(互相垂直)。

Sum of Angles at a Point

In the diagram, $\angle w$, $\angle x$, $\angle y$ and $\angle z$ share a common vertex at $O$ and each angle is adjacent to two other angles. These four angles are called angles at a point.

$\angle w + \angle x + \angle y + \angle z = 360°$.

w x y z R Q T S O
The sum of all angles at a point is 360°.
(Abbreviation: ∠s at a point)

📌 INVARIANCE: While all the angles on a straight line add up to 180°, all the angles at a point add up to 360°.

📖 Worked Example 3

Find the value of $x$ in the diagram (four angles at a point: $3x°$, $x°$, $72°$, $4x°$).

3x° 72° 4x°

SOLUTION

  • $x + 3x + 4x + 72 = 360$  (∠s at a point)
  • $8x + 72 = 360$
  • $8x = 288$
  • ∴ $x = \mathbf{36}$
✍️ Try It Yourself 3

Find the value of $x$ in the diagram (three angles at a point: $5x°$, $3x°$ on top, $x°$ on left).

5x° 3x°

$x = $ 检查

💡 思路

水平线已确定 180°;上方三个角加 5x、3x 都在直线上方,合 = $x + 5x + 3x = 9x = 180$?或者 4 个角合 360°?
若三个角在直线上方 + 一个未标角在直线下方(180°):$x + 5x + 3x = 180 \Rightarrow 9x = 180 \Rightarrow x = 20$。
若全部在一点周围:$x + 5x + 3x = 360 \Rightarrow 9x = 360 \Rightarrow x = 40$。
根据图示有"水平线"(直线在底)且三个角向上方分布,正确解读是直线上方:$9x = 180 \Rightarrow x = 20$.

Vertically Opposite Angles

In the diagram, two straight lines $AB$ and $CD$ intersect at the point $O$ and form four angles. The pairs of angles, $\angle a$ and $\angle b$ as well as $\angle x$ and $\angle y$, are called vertically opposite angles.

$\angle a = \angle b$   and   $\angle x = \angle y$.

x a b y C B D A O
When two straight lines intersect, the vertically opposite angles are equal.
(Abbreviation: vert. opp. ∠s)

📌 SPOTLIGHT (Proof):
$\angle a + \angle x = 180°$  (adj. ∠s on a st. line)
$\angle b + \angle x = 180°$  (adj. ∠s on a st. line)
∴ $\angle a + \angle x = \angle b + \angle x \Rightarrow \angle a = \angle b$. ✓

In each diagram below, are $\angle a$ and $\angle b$ vertically opposite angles? Explain.
💡 思考

"对顶角"必须是两条直线相交所形成的对位角。
• 如果两条线在同一交点相交且对位,✓
• 如果只有一条直线(另一条是折线/不通过交点):✗
• 如果两条线不延伸过交点的另一侧:✗

📖 Worked Example 4

In the diagram, $AD$, $BE$ and $CF$ are straight lines intersecting at $G$. The angle $\angle AGF = 80°$ and angles $y$ on both sides as shown. Find $\angle y$.

F E D C B A 80° y y G

SOLUTION

  • $\angle BGC = 80°$  (vert. opp. ∠s)
  • $\angle AGB + \angle BGC + \angle CGD = 180°$  (adj. ∠s on a st. line)
  • $\angle y + 80° + \angle y = 180°$
  • $2\angle y = 100°$
  • ∴ $\angle y = \mathbf{50°}$

📌 SPOTLIGHT: If an angle is marked without the symbol (°), such as $y$, then the final answer for $y$ must have a value and a unit which is degree.

✍️ Try It Yourself 4

In the diagram, $PS$, $QT$, $RU$ are straight lines intersecting at $V$. The marked angles are $3z$, $70°$, and $(2z + 15)°$. Find the value of $\angle z$.

U T S R Q P 3z° (2z+15)° 70° V

$z = $ 检查

💡 思路

$P, V, S$ 共线,所以 $\angle PVU + \angle UVT + \angle TVS = 180°$,即 $3z + 70 + (2z+15) = 180$(如果 70 在 $UVT$ 位置)。
$3z + 70 + 2z + 15 = 180 \Rightarrow 5z + 85 = 180 \Rightarrow 5z = 95 \Rightarrow z = 19$.

PPractice Exercise 6.2

BASIC MASTERY
  1. Q1. Classify each of the marked angles in the figure (a stylised dancer pose) as acute, obtuse, right or reflex.
    (a) $\angle a$ → 检查
    (b) $\angle b$ → 检查
    (c) $\angle c$ → 检查
    (d) $\angle d$ → 检查

    (分类基于角的大小;具体角值取决于课本图示。常见答案如上。)

  2. Q2. $AOB$ is a straight line. Find each unknown marked angle.
    (a) $E$, $40°$, $a°$, $F$ marked at $O$ on st line $AOB$. The angles between $OE$ and $OA$ is given (40°), between $OE$ and $OF$ is $a°$, and on the other side of $OF$ also 40° (mirror). Find $a$. → 检查
    (b) $P$, $R$, $B$, $Q$ angles with $61°, b°, 31°, 18°$ on st line $AOB$. → $b = $ 检查
    💡 思路

    (a) $40 + a + 40 = 180 \Rightarrow a = 100°$.
    (b) $61 + b + 31 + 18 = 180 \Rightarrow b = 70°$.

  3. Q3. Find the unknown angle $x$ in each diagram.
    (a) Four angles around a point: $64°$, $90°$ (right-angle mark), $x°$, $125°$. → $x = $ 检查
    (b) Five angles around a point: $60°$, $x°$, $54°$, $78°$, $89°$. → $x = $ 检查
    💡 思路

    (a) $360 - 64 - 90 - 125 = 81$.
    (b) $360 - 60 - 54 - 78 - 89 = 79$.

  4. Q4. Find the value of $y$ in the diagram (three equal angles $y°$, $y°$, $y°$ at a point).
    $y = $ 检查
    💡 思路

    $3y = 360 \Rightarrow y = 120°$.

  5. Q5. In each diagram, lines $AB$ and $CD$ intersect at a point. Find the unknown marked angles.
    (a) $\angle EAC = 33°$ (or similar); find $x$ and $y$.
    $x = $ $y = $ 检查
    💡 思路

    $y$ 与 33° 是对顶角 → $y = 33°$. $x$ 与 33° 是邻角(一条直线上)→ $x = 180 - 33 = 147°$。


    (b) Three lines through $F$; $76°, 128°$ given; find $p$ and $q$.
    $p = $ $q = $ 检查
    💡 思路

    两条直线交于 F,4 个角;$76°$ 和 $128°$ 是相邻的(合 = 204° ≠ 180°),所以实际上是三条直线。$p$ 与 76° 是对顶角 → $p = 76°$;$q$ 与 128° 是对顶角 → $q = 128°$。

  6. Q6. $AB$ is a plane mirror. A light ray $PQ$ hits the mirror at $Q$ and is reflected along $QR$ such that $\angle AQP = \angle BQR = x°$. If $\angle PQR = 110°$, find $x$.
    $x = $ 检查
    💡 思路

    $AQB$ 直线 → $x + 110 + x = 180 \Rightarrow 2x = 70 \Rightarrow x = 35°$。

  7. Q7. $LMN$ is a straight line. At $M$, an angle of 134° is given on the left (between $LM$ and a ray $MQ$ going down). Three rays $MP, MQ, MN$ on the right (from $M$): $y°$ (between $MN$ and one of the rays), $x°$ (between two rays).
    (a) Find $y$. → 检查
    (b) Type of angle $\angle PMN$? → 检查
         Type of angle $\angle LMN$? → 检查
    💡 思路

    (a) 134° 和 $y$ 在直线 $LMN$ 同一边相邻 → $y = 180 - 134 = 46°$.
    (b) $\angle PMN$ < 90° → 锐角。
    $\angle LMN = 180°$ → 平角 (straight angle).

  8. Q8. Find the value of $x$ in the diagram (around a point: $3x°$, $50°$, $x°$, $4x°$, $70°$).
    $x = $ 检查
    💡 思路

    $3x + 50 + x + 4x + 70 = 360 \Rightarrow 8x + 120 = 360 \Rightarrow x = 30$.

INTERMEDIATE
  1. Q9. (OPEN) In the diagram, $E$, $F$, $D$ are rays from $B$ on st. line $ABC$. Name (a) two acute angles, (b) two obtuse angles in the diagram.
    Two acute angles: 检查
    Two obtuse angles: 检查

    (开放题,根据图示判断。每个标记角自己分类。)

  2. Q10. In each of the following diagrams, three lines intersect at a point. Find the value of $x$.
    (a) Two angles $(5x-2)°$ and one of $84°$ with $(5x-2)°$ on top, $84°$ on st. line: → $x = $ 检查
    (b) Three lines, angles labelled $x°$, $2x°$, $2x°$ on one side: → $x = $ 检查
    💡 思路

    (a) 三角 (5x-2), 84, (5x-2) 在直线上 → $2(5x-2) + 84 = 180 \Rightarrow 10x = 100 \Rightarrow x = 10$.
    (b) $x + 2x + 2x = 180 \Rightarrow 5x = 180 \Rightarrow x = 36$.

  3. Q11. Lines $AD$, $BE$, $CF$ intersect at $G$. $\angle AGF = 38°$, $\angle EGD = 55°$. Find $\angle FGE = a°$, $\angle DGC = b°$, $\angle CGB = c°$.
    $a = $ ; $b = $ ; $c = $ 检查
    💡 思路

    $AD$ 是直线,3 个角加起来 = 180°:$38 + a + 55 = 180 \Rightarrow a = 87°$。
    $b$ 与 $\angle AGF = 38°$ 对顶 →?等等,$b$ 是 $\angle DGC$。检查角对位:$BE$ 直线两端 $B$ 和 $E$;$CF$ 两端 $C, F$。
    $\angle DGC$ 在 $b$ 的位置是 $\angle EGD$ 对顶 → $b = \angle EGD = 55°$.
    $c = \angle CGB$ 与 $\angle AGF = 38°$ 对顶 → $c = 38°$.

  4. Q12. The diagram shows a pair of tongs (two crossed bars). Angles at the pivot: $2x°$ (top), $7x°$ (left), $y°$ (right). Find $x$ and $y$.
    $x = $ ; $y = $ 检查
    💡 思路

    钳子是两条相交的直线,4 个角,$2x$ 和 $7x$ 相邻(在直线上):$2x + 7x = 180 \Rightarrow x = 20$. $y$ 与 $7x$ 对顶 → $y = 7(20) = 140°$.

  5. Q13. The time shown on the clock is 4 o'clock. Find reflex $\angle AOB$ (where $A$ is at the hour hand, $B$ at the minute hand). → ° 检查
    💡 思路

    钟面平均分 12 区,每区 $360°/12 = 30°$。4 点钟时分针在 12,时针在 4,相隔 4 个区 → 顺时针小角度 = $4 \times 30° = 120°$。反射角 = $360° - 120° = 240°$.

ADVANCED
  1. Q14. Two angles are vertically opposite angles. What is the size of each angle if the two angles are
    (a) complementary angles (sum 90°)? → ° 检查
    (b) supplementary angles (sum 180°)? → ° 检查
    💡 思路

    对顶角相等,所以两个角相等。$x + x = 90 \Rightarrow x = 45°$. 或 $x + x = 180 \Rightarrow x = 90°$.

  2. Q15. $\angle x$ and $\angle y$ are the only two adjacent angles on a straight line. Find $\angle x$ if
    (a) $\angle x = \angle y$. → ° 检查
    (b) $\angle x = 3\angle y$. → ° 检查
    💡 思路

    $x + y = 180$. (a) $2x = 180 \Rightarrow x = 90°$. (b) $3y + y = 180 \Rightarrow y = 45°, x = 135°$.

  3. Q16. In the diagram, $\angle PQT = 2\angle RQS$ and $\angle TQS = 5\angle RQS$. Write an equation in $x$ and solve it to find the size of $\angle TQS$. ($PQR$ is a straight line with $T$, $S$ as additional rays from $Q$.)
    $\angle TQS = $ ° 检查
    💡 思路

    Let $\angle RQS = r$. Then $\angle PQT = 2r$, $\angle TQS = 5r$. $PQR$ 直线 → $2r + 5r + r = 180 \Rightarrow 8r = 180 \Rightarrow r = 22.5°$. $\angle TQS = 5 \times 22.5 = 112.5°$.

  4. Q17. It is given that $OB \perp OD$ and $\angle AOB = \angle COD$. What is the relationship between $OA$ and $OC$?
    Relationship: 检查
    💡 思路

    $\angle BOD = 90°$. $\angle AOC = \angle AOB + \angle BOC$;$\angle BOC = \angle BOD - \angle COD = 90 - \angle COD$. 又 $\angle AOC = \angle AOB + (90 - \angle COD) = 90 + (\angle AOB - \angle COD) = 90 + 0 = 90°$. 所以 $OA \perp OC$.

  5. Q18. In the diagram, $AD$, $BE$, $CF$ are straight lines which intersect at $G$. Angles: $x°$ (between $FG$ and $AG$, top-left), $y°$ (between $BG$ and $AG$, bottom-left), $50°$ (between $EG$ and $DG$).
    (a) Find $x° + y°$. → ° 检查
    (b) Suggest two possible pairs of values of $x$ and $y$. 检查
    (c) If $y = 3x$, find $x$ and $y$. → $x = $ ; $y = $ 检查
    💡 思路

    (a) $AD$ 直线,3 角同侧加起来 180°:$x + 50 + y = 180 \Rightarrow x + y = 130°$.
    (b) 任意满足和为 130 的对,比如 $(30, 100), (50, 80), (60, 70)$...
    (c) $3x + x = 130 \Rightarrow 4x = 130 \Rightarrow x = 32.5°, y = 97.5°$.

  6. Q19. (a) A circular pizza is divided into 10 equal pieces by 5 cuts through its centre. Find $\angle x$ (one piece). → ° 检查
    (b) Another pizza is divided into equal pieces with each piece = $22.5°$. How many cuts are made?
    Cuts = 检查
    💡 思路

    (a) 360° / 10 = 36°.
    (b) 360 / 22.5 = 16 块;每刀切出 2 块新区 → 16 / 2 = 8 刀